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Volume of Gases and Number of Moles

One litre of ...

Question

One litre of ${C O}_{2}$ is passed over hot coke. The volume becomes $1.4$ lit. The resultant mixture contains:

0.6

lit

{C O}_{2}

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0.6

lit

C O

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0.8

lit

C O

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0.87

lit

{C O}_{2}

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Solution

The correct option is B $0.6$ lit ${C O}_{2}$
$C O_{2} + C ⟶ 2 C O$
$1$ $m o l e$ of $C O_{2}$ and $1$ $m o l e$ of $C$ gives $2$ moles of $C O$
If, $X L$ of $C O_{2}$ react $⟶$ $2 X$ litres of $C O$
$∴$ Total volume $= C O_{2} + C O$
$\Rightarrow (V o l u m e o f C O_{2})_{n e w} + (V o l u m e o f C O)_{n e w} = 1.4$ (equation 1)
Also:
$(V o l u m e o f C O_{2})_{n e w} = (V o l u m e o f C O_{2})_{i n i t i a l} - (V o l u m e o f C O_{2})_{r e a c t e d}$
$\Rightarrow (V o l u m e o f C O_{2})_{n e w} = 1 - x$
And, $V o l u m e o f C O = 2 X$
Using these two in eqution $01$
$(1 - x) + 2 x = 1.4$
$\Rightarrow x = 0.4 L$
$∴ (V o l u m e o f C O_{2})_{r e a c t e d} = 0.4 L$
$\Rightarrow (V o l u m e o f C O_{2})_{r e m a i n i n g} = (1 - 0.4) L = 0.6 L$

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