Question

One mol of a monoatomic gas is mixed with one mol of a diatomic gas. The molar specific heat of mixture at constant volume will be

• A. $\frac{R}{2}$
• B. $R$
• C. $2R$
• D. $3R$

Answer 1

The correct option is C $2R$

The molar specific heat of mixture at constant volume is given by

$C=C_1+C_2$

For monoatomic gas, $C_1=\frac{3}{2}R$

For diatomic gas,$C_2=\frac{5}{2}R$

so, $C=2R$

Hence, option C is correct