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Van't Hoff Factor

One mole of a...

Question

One mole of a solute A is dissolved in a given volume of a solvent. If solute undergoes association, it's Van't Hoff factor i is expressed as:

A

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B

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C

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D

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Solution

The correct option is C

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when dissolved in a solvent associate to form a pentamer. The value of van't Hoff factor (

i

) for the solute will be:

Q. Certain substance trimerizes when dissolved in a solvent, A. The Van't Hoff factor for the solution is:

The electrolyte solutions show abnormal colligative properties. To account for this effect we define a quantity called the Van't Hoff factor given by :

i = \frac{Actual number of particles in solution after dissociation/association}{Number of formula units initially dissolved in solution}

i = 1

(for non-electrolytes)

i > 1

(for non-electrolytes, undergoing dissociation)

i < 1

(for solutes, undergoing dissociation)

Answer the following questions:

A solution of benzoic acid is dissolved in benzene such that it undergoes molecular association and its molar mass approaches 244. The benzoic molecules will exist as :

Q. The Van't Hoff factors

i

for an electrolyte which undergoes dissociation and association in solvents are respectively:

Q. A dilute solution contains

^{'} x^{'}

moles of solute

A

1 kg

of solvent with molal elevation constant

K_{b}

. The solute dimerises in the solution according to the following equation.

2 A ⇌ A_{2}

The degree of association is

(α)

. The van't Hoff factor (i) will be :
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