One mole of Al is deposited by X coulombs of charge by passing through molten AlCl3. The number of moles of Ag deposited by the same charge from silver nitrate solution is
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is C
3
Al3+ + 3 e (r) Al ; Ag+ + e (r) Ag 'X' mole deposit 1 mole of Al, hence 'X'=3 1 mole electrons deposit ------1 mole Ag