One mole of an ideal gas expands against a constant external pressure of 1 atm from a volume of $10 d m^{3}$ to a volume of $30 d m^{3}$ . What would be the work done in joules?

- 2026 J

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+ 2026 J

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- 1947 J

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1648 J

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Solution

The correct option is A $- 2026 J$
$\begin{matrix} W o r k d o n e f o r i s o t h e r m a l a n s i o n, W = - \int_{V_{1}}^{V_{2}} p d V S i n c e, ρ i s c o n s tan t, W = - \int_{V_{1}}^{V_{2}} d V W = - ρ (V_{2} - V_{1}) W = - 1 a t m (30 - 10) L = - 20 a t m L N o w, 0.08206 L a t m = 8.314 J (A s w e k n o w) - 20 a t m L = \frac{8.314}{0.08206} \times - 20 J = - 2026.32 J \end{matrix}$
Hence,
option $(A)$ is correct answer.

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