One mole of an ideal gas undergoes a process : P=P01+(V0/V)2
Here P0 and V0 are constants. Change in temparature of the gas when volume is changed from V=V0 to V=2V0 is
A
−2P0V05R
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B
11P0V010R
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C
−5P0V04R
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D
P0V0
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Solution
The correct option is B11P0V010R At V=V0:P=P02 ∴T1=PVnR=(P02)V0R=P0V02R(n=1)
and at V=2V0:P=4P05
∴Tf=PVnR=(2V0)(4P05)R=8P0V05R
∴ΔT=Tf−Ti=(85−12)P0V0R=11P0V010R
Hence, the correct answer is option (b).