1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Heat of Reaction
One mole of a...
Question
One mole of an ideal gas undergoes a process P=P0/(2+V0/V),(where P0 and V0 are constant).Change in temperature of the gas when volume is changed from V=V0 to V =3V0 is
Open in App
Solution
Suggest Corrections
0
Similar questions
Q.
One mole of an ideal gas undergoes a process
P
=
P
0
1
+
(
V
0
V
)
2
Here
P
0
and
V
0
are constants. Change in temperature of the gas when volume is changed from
V
=
V
0
to
V
=
2
V
0
is :-
Q.
One mole of an ideal gas undergoes a process :
P
=
P
0
1
+
(
V
0
/
V
)
2
Here
P
0
and
V
0
are constants. Change in temparature of the gas when volume is changed from
V
=
V
0
to
V
=
2
V
0
is
Q.
One mole of an ideal gas u ndergoes a process:
P
=
P
0
1
+
(
V
0
/
V
)
2
.
Here
P
0
and
V
0
are constants. change in temperature of the gas when volume is changed from
V
=
V
0
to
V
=
2
V
0
is:
Q.
One mole of an ideal gas undergoes a process
P
=
P
0
(
1
+
(
2
V
0
V
)
2
]
−
1
,
where
P
0
,
V
0
are constants. Change in temperature of the gas when volume is changed from
V
=
V
0
to
V
=
2
V
0
is
n
P
o
V
0
R
. Then
n
is