Question

One mole of an ideal gas undergoes an isothermal change at temperature T so that its volume V is doubled. R is the molar gas constant. Work done by the gas during this change is :

• A. RT $\ln 4$
• B. RT $\ln 3$
• C. RT $\ln 2$
• D. RT $\ln 1$

Answer 1

The correct option is C RT $\ln 2$

Under isothermal process work is given by the relation $W=RT\ln \left(\frac{V_f}{V_i}\right)$
Therefore work will be $W=RT\ln \left(2\right)$