One mole of butane is burnt in excess oxygen and the gas produced is allowed to pass through a 3 M lime water solution having 1 L volume. The mole(s) of CaCO3 formed is .
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Solution
Combustion of hydrocarbons produce CO2 gas.
C4H10+132O2→4CO2+5H2O CO2 produced is allowed to pass through Ca(OH)2, the reaction is: CO2+Ca(OH)2→CaCO3+H2O
Since only 3 moles of Ca(OH)2 are present, only 3 moles of CaCO3 will be formed.