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Gay Lussac's Law, Avagadro's Law

One mole of m...

Question

One mole of mixture of $C H_{4}$ and air (containing 80% $N_{2}$ 20% $O_{2}$ by volume) of a composition such that when underwent combustion gave maximum heat (assume combustion of only $C H_{4}$ . Then which of the statements are correct, regarding composition of initial mixture. (X presents mole fraction)

A

XCH₄ =O2 =

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B

XCH₄ = =

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C

XCH₄=1/6XO₂ =X_N2 =2/3

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D

Data insufficient

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Solution

The correct option is A
XCH₄ =O2 =

$C H_{4}$ + $O_{2}$ $⟶$ $C O_{2}$ +2 $H_{2} O$

Xmole 1-x mole

$n_{(0_{2})}$ = 0.2(1-x)

For complete combustion

$\frac{n_{C H_{4}}}{1}$ = $\frac{n o_{2}}{1}$

$\frac{x}{1}$ = $\frac{0.2 (1 - x)}{2}$

2x =0.2-0.2x

2-2x =0.2

X = $\frac{x}{11}$

$X_{C H_{4}}$ = $\frac{1}{11}$

$X_{O_{2}}$ = $\frac{2}{11}$ $X_{(N_{2})}$ = $\frac{8}{11}$

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Similar questions

Q. One mole mixture of C

H_{4}

& air (containing 80%

N_{2}

O_{2}

by volume) of a composition such that when underwent combustion gave maximum heat (assume combustion of only

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Q. A mixture of

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