Question

One mole of $N_2{H}_4$ loses $10$ moles of electrons to form a new compound $A$. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in $A$?

[There is no change in the oxidation state of hydrogen]

• A. $+1$
• B. $-3$
• C. $+3$
• D. $+5$

Answer 1

The correct option is C $+3$

The oxidation state of N in hydrazine is -2.

1 mole of hydrazine contains 2 moles of N and loses 10 moles of electrons. Hence, 1 N atom will lose 5 electrons. Hence, its oxidation number will increase by 5.

Hence, the oxidation number of N in compound A will be $-2+5=+3$.

Hence, the correct option is $C$