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Question

A mole of N2H4 loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? ( There is no change in the oxidation number of hydrogen. )

A
--1
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B
-3
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C
3
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D
5
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Solution

The correct option is C 3
From the given information , we have
N2H4Y+10e
Number of N in Y is 2
Let the oxidation number of N be 'x'.
Oxidation number of H=+1
In N2O4: 2x+4×1=0
or x=2
The oxidation state of N in N2H4=2
The two nitrogen atoms in Y will balance the charge of 10e where each N losses 5 electron. Hence oxidation state of N changes from -2 to 2+5=+3.

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