CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

One mole of one of the sodium salts listed below, having carbon content close to 14.3%, produces 1 mole of carbon dioxide upon heating (atomic mass Na=23,H=1,C=12,O=16). The salt is :

A
C2H5COONa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
NaHCO3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
HCOONa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
CH3COONa
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B NaHCO3
Given
Carbon content in sodium salt is 14.3%
It produces 1 mole of CO2
Solution
1) C2H5COONa
Molecular Mass = 12*2+5*1+12+16+16+23= 96
Percentage of C in it =1296100=12.5

2) NaHCO3
Molecular Mass = 23+1+12+3*16= 84
Percentage of C in it =1284100=14.28

3) HCOONa
Molecular Mass= 1+12+16+16+23= 68
Percentage of C in it =1268100=17.64

4) CH3COONa
Molecular Mass= 12+3*1+12+16+16+23= 82
Percentage of C in it =1282100=14.63
The correct option is B

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sodium Carbonate
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon