Question

Sodium bicarbonate breaks down on heating:
$2NaHC{O}_3\to N{a}_{2}C{O}_3+H_{2}O+C{O}_2$
(Atomic mass of $Na=23,C=12,H=1,O=16)$
i) How many moles of sodium bi carbonate are there in the equation?
ii) What is the mass of sodium bicarbonate used in this equation?
iii) How many moles of carbon dioxide are there in this equation?

Answer 1

(i) From the given equation, it is clear that there are $2$ moles of sodium bicarbonate.

(ii) Mass of $NaHC{O}_3$ used= $2\times$ Molar mass of $NaHC{O}_3$

$=2\times (23+1+12+16\times 3)$

$=168g$

(iii) From given equation, $1$ mole of carbon dioxide is formed.