Question

One mole of oxygen gas at STP is equal to_____.

• A. $6.022\times {10}^{23}$ molecules of oxygen
• B. $6.022\times {10}^{23}$ atoms of oxygen
• C. $16\text{g}$ of oxygen.
• D. $32\text{g}$ of oxygen.

Answer 1

Answer: (A), (D)

$32\text{g}$ of oxygen.

1 mole of $O_2$ gas at STP = $6.022\times {10}^{23}$ molecules of $O_2$ (Avogadro’s number)
1 mole of $O_2$ gas at STP = $32\text{g}$ of $O_2$
Hence, 1 mole of oxygen gas is equal to the molar weight of oxygen gas as well as the Avogadro’s number.