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Isomerism

one mole of P...

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one mole of PCl5 is heated in one litre container . if 0.6 moles of chlorine is at equilibrium How to calculate the value of equilibrium constant?

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P C l_{5}

is heated with 0.2 mole of chlorine in a one litre vessel till equilibrium is established.At equilibrium if 0.8 mole of chlorine is present in the vessel, the equilibrium constant for the dissociation of

P C l_{5}

Q. A vessel of one litre capacity containing

1

{S O}_{3}

is heated till a state of equilibrium is attained.

2 {S O}_{3 (g)} ⇌ 2 {S O}_{2 (g)} + O_{2 (g)}

At equilibrium,

0.6

{S O}_{2}

had formed. The value of equilibrium constant is:

2

P C l_{5}

were heated in a closed vessel of 2 litre capacity. At equilibrium,

40 %

P C l_{5}

is dissociated into

P C l_{3}

C l_{2}

. The value of equilibrium constant is-

P C l_{5},

were heated in a closed vessel of 2 litre capacity. At equilibrium, 40% of

P C l_{5}

is dissociated into

P C l_{3} a n d C l_{2} .

The value of equilibrium constant is

Q. Two moles of

P C l_{5}

were heated in closed vessel of 2 litre capacity. At equilibrium, 40% of

P C l_{5}

was dissociated into

P C l_{3}

C l_{2}

The value of the equilibrium constant is :

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