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Stoichiometric Calculations

One mole of ...

Question

One mole of $S O_{2} C l_{2}$ is dissolved in water and $C a (O H)_{2}$ is added to neutralise acidic solution. Number of moles of $C a (O H)_{2}$ required is :

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Solution

The balanced reactions are as follows:
$S O_{2} C l_{2} + 2 H_{2} O ⟶ H_{2} S O_{4} + 2 H C l$
$H_{2} S O_{4} + C a (O H)_{2} ⟶ C a S O_{4} + 2 H_{2} O$
$2 H C l + C a (O H)_{2} ⟶ C a C l_{2} + 2 H_{2} O$
Thus, total $C a (O H)_{2}$ required $= 2$ mol
Hence,2 moles of $C a (O H)_{2}$ required.

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