One mole of SO3 was placed in a 1 lit. reaction vessel at a constant temperature. The following equilibrium was established: 2SO3⇔2SO2+O2. At equilibrium, 0.6 moles of SO2 were formed. The equilibrium constant of the reaction will be:
SO3 | SO2 | O2 | |
Initial | 1 | 0 | 0 |
Change | -2x | 2x | x |
Equilibrium | -2x | 2x | x |