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Enthalpy of Solution

One mole of s...

Question

One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissolution of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

A

- 92 kJ

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B

+ 42 kJ

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C

- 42 kJ

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D

-102 kJ

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Solution

The correct option is A - 92 kJ
Given- $△_{s o l n} = - 25 k J$ , $△ H_{l} = 67 k J$
From Hess's law
$△_{s o l n} = △ H_{l} + △ H_{h y d r a t i o n}$
$- 25 = + 67 + △ H_{h y d r a t i o n}$
$\Rightarrow △ H_{h y d r a t i o n} = - 92 k J$

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Enthalpy of Solution

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