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Factors Affected by Hydrogen Bonding

One mole of s...

Question

One mole of soda ash dissolves in water with evoution of 25 kJ of heat. Dissolution of 1 mol of the hydragte crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

A

- 92 kJ

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B

+ 42 kJ

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C

-42 kJ

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D

-102 kJ

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Solution

The correct option is A - 92 kJ
From hess's law
$△ H_{s o l n} (a n h y d r o u s s a l t) = △ H_{h y d r a t i o n} + △ H_{s o l u t i o n} (h y d r a t e d s a l t) \Rightarrow △ H_{h y d r a t i o n} = (- 25 k J) - (+ 67 k J) △ H_{h y d r a t i o n} = - 92 k J$

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Similar questions

Q. One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissolution of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

Q. One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissociation of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

Q. One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissolution of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

Q. One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissociation of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

Q. One mole of anhydrous

M g C l_{2}

dissolve in water and liberates

25

cal/mol of heat.

Δ H_{h y d r a t i o n}

M g C l_{2} = - 30

cal/mol. Heat of dissolution of

M g C l_{2} \cdot H_{2} O

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Factors Affected by Hydrogen Bonding

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