One of Saturn's moon is named as Mimas. The orbital radius of Mimas is 1.87 $\times$ $10^{8}$ m. The time taken to complete one revolution by Mimas around Saturn is approximately 23 hours. The speed of Mimas with which it revolves around Saturn is

21,274 m/s

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7,091 m/s

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28,366 m/s

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14,183 m/s

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Solution

The correct option is D
14,183 m/s

Given, Orbital radius of Mimas R = 1.87 $\times$ $10^{8}$ m and time taken to complete 1 revolution T = 23 hours

Speed = $\frac{C i r c u m f e r e n c e o f c i r c u l a r p a t h}{T i m e p e r i o d}$

= $\frac{2 π R}{T}$

= $\frac{2 \times 3.14 \times 1.87 \times 10^{8}}{23 \times 3600}$

= 14183 $m s^{- 1}$

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One of Saturn's moon is named as Mimas. The orbital radius of Mimas is 1.87 × 108 m. The time taken to complete one revolution by Mimas around Saturn is approximately 23 hours. The speed of Mimas with which it revolves around Saturn is

The correct option is D 14,183 m/s Given, Orbital radius of Mimas R = 1.87 × 108 m and time taken to complete 1 revolution T = 23 hours Speed = Circumference of circular pathTime period = 2πRT = 2×3.14×1.87×10823×3600 = 14183 ms−1

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