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Question

# One of saturn's moon is named as Mimas. The orbital radius of Mimas is 1.87× 108 m from saturn. The mean orbital period of Mimas is approximately 23 hours. Calculate the speed of Mimas with which it revolves around saturn. Assume that the path taken is circular.

A
21,274 ms1
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B
7,091 ms1
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C
28,366 ms1
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D
14,183 ms1
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Solution

## The correct option is D 14,183 ms−1Given, Orbital radius, R=1.87×108 m Time period: T=23 hours T=23×3600=82,800 s From definition of speed, Speed=CircumferenceTime period v=2πRT v=2×3.14×1.87×10882,800 v=14183 ms−1 ∴Speed of Mimas with which it revolve around saturn is 14183 ms−1.

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