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Byju's Answer
Standard IX
Mathematics
Laws of Exponents for Real Numbers
One of the fa...
Question
One of the factor of
∣
∣ ∣ ∣
∣
p
2
+
x
p
q
p
r
p
q
q
2
+
x
q
r
p
r
q
r
r
2
+
x
∣
∣ ∣ ∣
∣
is
A
x
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B
(
p
2
+
x
)
(
q
2
+
x
)
(
r
2
+
x
)
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C
(
p
2
+
q
2
+
r
2
+
x
)
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D
None of these
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Solution
The correct option is
C
(
p
2
+
q
2
+
r
2
+
x
)
∣
∣ ∣ ∣
∣
p
2
+
x
p
q
p
r
p
q
q
2
+
x
q
r
p
r
q
r
r
2
+
x
∣
∣ ∣ ∣
∣
1
p
q
r
∣
∣ ∣ ∣
∣
p
(
p
2
+
x
)
p
2
q
p
2
r
p
q
2
q
(
q
2
+
x
)
q
2
r
p
r
2
q
r
2
r
(
r
2
+
x
)
∣
∣ ∣ ∣
∣
∣
∣ ∣ ∣
∣
(
p
2
+
x
)
p
2
p
2
q
2
(
q
2
+
x
)
q
2
r
2
r
2
(
r
2
+
x
)
∣
∣ ∣ ∣
∣
R
1
→
R
1
+
R
2
+
R
3
∣
∣ ∣ ∣
∣
(
p
2
+
q
2
+
r
2
+
x
)
(
p
2
+
q
2
+
r
2
+
x
)
(
p
2
+
q
2
+
r
2
+
x
)
q
2
(
q
2
+
x
)
q
2
r
2
r
2
(
r
2
+
x
)
∣
∣ ∣ ∣
∣
(
p
2
+
q
2
+
r
2
+
x
)
∣
∣ ∣ ∣
∣
1
1
1
q
2
(
q
2
+
x
)
q
2
r
2
r
2
(
r
2
+
x
)
∣
∣ ∣ ∣
∣
C
1
→
C
1
−
C
3
(
p
2
+
q
2
+
r
2
+
x
)
∣
∣ ∣ ∣
∣
0
1
1
0
(
q
2
+
x
)
q
2
−
x
r
2
(
r
2
+
x
)
∣
∣ ∣ ∣
∣
Clearly one factor of the determinant is
(
p
2
+
q
2
+
r
2
+
x
)
Suggest Corrections
0
Similar questions
Q.
Factorize :
(
p
2
−
2
p
q
+
q
2
)
−
r
2
Q.
The expression
x
2
−
4
p
x
+
q
2
>
0
for all real
x
and also
r
2
+
p
2
<
p
r
,then the range of
f
(
x
)
=
x
+
r
x
2
+
q
x
+
p
2
is
Q.
Given that the function
f
(
x
)
=
(
x
−
p
)
2
+
(
x
−
q
)
2
+
(
x
−
r
)
2
has a minimum, find the corresponding values of
x
Q.
Factorize the polynomial,
−
r
2
+
p
2
+
q
2
−
2
p
q
.
Q.
Using quadratic formula, find the value of x.
p
2
x
2
+
(
p
2
−
q
2
)
x
−
q
2
=
0
,
p
≠
0
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