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Question

One of the factors of a3+8b3−64c3+24abc is

A
a+2b4c
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B
a2b+4c
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C
a+2b+4c
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D
a2b4c
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Solution

The correct option is B a+2b4c
a3+8b364c3+24abc
=(a)3+(2b)3+(4c)33(a)(2b)(4c)
=(a+2b4c)(a2+4b2+16c22ab+8bc4ac)

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