One of the following conversion results in the change of hybridization and geometry:

{C H}_{4}

C_{2} H_{6}

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{N H}_{3}

+ N H_{4}

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{B F}_{3}

_{4}

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H_{2} O

H_{3} + O

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Solution

The correct option is D ${B F}_{3}$ to $_{4}$
In $B F_{3}$ hybridisation is $s p^{2}$ whereas in $B F_{4}^{-}$ hybridisation is $s p^{3}$

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Similar questions

Which of the following conversions involve change in both shape and hybridisation?

a) CH4 -> C2H6

b) NH3 -> NH4+

c) BF3 -> BF4-

d) H2O ->H3O+

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

B F_{3} - N H_{3}

C_{2} H_{4}

C_{2} H_{6}

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