One of the following having square planar structure is:

N H_{4}^{+}

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B F_{4}^{-}

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X e F_{4}

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S C l_{4}

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Solution

The correct option is A $X e F_{4}$
Among the given molecules, only $X e F_{4}$ will have the square planar structure because,the central atom has 8 valance electrons out of which 4 e- forms the sigma bond with F atom at the four corners of square in equatorial position while the 2 lone pair of electrons occupy axial position.

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Similar questions

Of the following species the one having a square planar structure is

_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{-}, B r F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -}

[P t C l_{4}]^{2 -}

X Z_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{-}, B r F_{4}^{-}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -} and [P t C l_{4}]^{2 -} .

X Z_{4}

X e F_{4}, S F_{4}, S i F_{4}, B F_{4}^{⊖}, [C u (N H_{3})_{4}]^{2 +}, [F e C l_{4}]^{2 -}, [C o C l_{4}]^{2 -} a n d [P t C l_{4}]^{2 -} .

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