One of the reactions that takes place in producing steel from iron ore is the reduction of iron II oxide by carbon monoxide to give iron metal and CO 2- FeO s - CO g - Fe s - CO 2 g - Kp-0-265 at 1050 KWhat are the equilibrium partial pressures of CO and CO 2 at 1050 K if the initial partial pressures are- p CO -1-4 atm and p CO 2-0-80 atm -

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Standard XII

Chemistry

Extraction of Copper

One of the re...

Question

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂.

FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K.

What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and = 0.80 atm?

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Solution

For the given reaction,

Since, the reaction will proceed in the backward direction.

Therefore, we can say that the pressure of CO will increase while the pressure of CO₂ will decrease.

Now, let the increase in pressure of CO = decrease in pressure of CO₂be p.

Then, we can write,

Therefore, equilibrium partial of

And, equilibrium partial pressure of

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Q. One of the reaction that takes place to producing steel from iron ore is the reduction of iron(III) oxide by carbon monoxde to give iron metal and

{C O}_{2}

F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{p} = 0.265

What are the equilibrium partial pressures of

C O

and

{C O}_{2}

1050 K

if the initial partial pressures are:

p_{C O} = 1.4 a t m

and

p_{{C O}_{2}} = 0.80 a t m

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂. FeO (s) + CO (g) Fe (s) + CO₂ (g); K_p= 0.265 at 1050 K. What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial partial pressures are: p_CO = 1.4 atm and CO₂ = 0.80 atm?