One packet of biscuits requires 3 cups of flour and $1 \frac{1}{3}$ cups of sugar, what will be the total quantity of both ingredients used in making 6 such packets of biscuits (in cups)?
26

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Solution

The correct option is A 26
1 packet needs $3 + 1 \frac{1}{3}$ cups of both ingredients.

$1 \frac{1}{3}$ also be written as $\frac{4}{3}$ .

$3 + \frac{4}{3} = \frac{3 (3) + 4}{3} = \frac{13}{3}$

1 packet needs $\frac{13}{3}$ cups of both ingredients.
6 packet need $\frac{13}{3} \times 6$ i.e $26$ cups of both ingredients.

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One packet of biscuits requires 3 cups of flour and 113 cups of sugar, what will be the total quantity of both ingredients used in making 6 such packets of biscuits (in cups)?26

The correct option is A 261 packet needs 3 + 113 cups of both ingredients. 113 also be written as 43. 3 + 43=3(3)+43=133 1 packet needs 133 cups of both ingredients. 6 packet need 133×6 i.e 26 cups of both ingredients.

One packet of biscuits requires 3 cups of flour and $1 \frac{1}{3}$ cups of sugar, what will be the total quantity of both ingredients used in making 6 such packets of biscuits (in cups)?
26