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Question

One train is approaching an observer at rest and another is receding him with same velocity 4 m/s. Both the trains blow whistles of same frequency of 243 Hz. The beat frequency in Hz as heard by the observer is: (Speed of sound in air = 320 m/s)

A
10
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B
6
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C
4
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D
1
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Solution

The correct option is C 6
Frequency when a source is approaching is, f1=(vvvs)f

Frequency when force is leaving is, f2=(vv+vs)f

Beats =f1f2=(2vvsv2v2s)f =(2×4×320(320)2(4)2)243 =6 Hz

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