Question

One type of liquid contains 25% of milk, the other contains 30% of milk. A container is filled with 6 parts of the first liquid and 4 parts of the second liquid. The percentage of milk in the mixture is:

• A. 27%
• B. 31%
• C. 29%
• D. 33%
• E. None of these

Answer 1

The correct option is A 27%

Let the amount of first liquid be $l_1$
Let the amount of second liquid be $l_2$
Amount of milk in first liquid = 25%($l_1$ ) = $\frac{l_1}{4}$
Amount of milk in second liquid = 30%($l_2$ ) = $\frac{{3l}_2}{10}$
Now the new mixture = ${6l}_1+{4l}_2$

To calculate the amount of milk in mixture = $\frac{Amountofmilk}{TotalMixture}$
$\%\text{milk}=\frac{6\times 25+4\times 30}{10}=27\%$