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Gay Lussac's Law, Avagadro's Law

One volume of...

Question

One volume of nitrogen combines with one volume of oxygen to form two volumes of nitric oxide. Calculate the amount of each reactant required to produce 250 ml of nitric oxide.

N_{2} = 100 m l, O_{2} = 100 m l

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N_{2} = 120 m l, O_{2} = 120 m l

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N_{2} = 125 m l, O_{2} = 125 m l

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N_{2} = 100 m l, O_{2} = 125 m l

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Solution

The correct option is C $N_{2} = 125 m l, O_{2} = 125 m l$
$N_{2} + O_{2} ⟶ 2 N O$
1 ml of $N_{2}$ reacts with 1 ml of $O_{2}$ to produce 2 ml of $N O$ .
So, to produce 250 ml of $N O$ , 125 ml of $N_{2}$ and $O_{2}$ are required.

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