ONE VOLUME OF NITROGEN GAS COMBINES WITH ONE VOLUME OF OXYGEN GAS TO FORM TWO VOLUMESOF NITRIC OXIDE CALCULATE THE AMOUNT OF EACH RESULTANT REQUIRED TO PRODUCE 250 ml OF NITRIC OXIDE

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Solution

$N_{2} + O_{2} \to 2 N O 1 v o l u m e o f n i t r o g e n c o m b i n e w i t h 1 v o l u m e o f o x y g e n t o g i v e 2 v o l u m e o f n i t r i c o x i d e . T h a t m e a n s 1 L o f n i t r o g e n c o m b i n e w i t h 1 l i t r e o f o x y g e n t o g i v e 2 L o f N O . T o p r o d u c e 250 m l o f n i t r i c o x i d e t h e a m o u n t o f n i t r o g e n n e e d e d i s = \frac{1}{2} \times 250 = 125 m l T o p r o d u c e 250 m l o f n i t r i c o x i d e t h e a m o u n t o f o x y g e n n e e d e d i s = \frac{1}{2} \times 250 = 125 m l$

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