Open end mercury manometer is connected to a gas chamber containing gas at a pressure of 1.38 bar. The barometric pressure is 750 mm Hg. Mercury level in the arm connected to a gas chamber stands at 11.3 cm. What is the reading in open arm of the manometer?
Gas pressure =1.38 bar
barometric pressure =750
Arm connected to gas chamber reads 11.3 cm
Excess pressure = open arm reading - 11.3
= x-11.3 cm =(x-11.3)×10mm
Total pressure of gas = 750 + (x-11.3)×10 mm
Now 760 mm pressure =1 bar
So 1.38 bar = 1.38×760=1048.8mm
1048.8= 750+(x-11.3)×10
x=(1048.8-750+113)/10
=310.1mm
Reading in open atm of manometer =310.1mm