Order and degree of x3d3ydx3-2x2d2ydx2-6y-x4 are-

The correct option is B 3,1 x^3y_3+2x^2y_2+6y=x^4 ⇒ order = 3degree = 1 nbsp; ...

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Order of a Differential Equation

Order and deg...

Question

Order and degree of $x^{3} \frac{d^{3} y}{d x^{3}} + 2 x^{2} \frac{d^{2} y}{d x^{2}} + 6 y = x^{4}$ are:

3, 1

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1, 3

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3, 2

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2, 2

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(2 x + 3 y) {(\frac{d y}{d x})}^{3} + 7 x \frac{d^{2} y}{d x^{2}} + y = e^{2 x}

For the following differential equation givne below indicate its order and degree (when defined)

$\frac{d^{2} y}{d x^{2}} + 5 x {(\frac{d y}{d x})}^{2} - 6 y = l o g x$

${(\frac{d y}{d x})}^{3} - 4 {(\frac{d y}{d x})}^{2} + 7 y = s i n x$

$\frac{d^{4} y}{d x^{4}} - s i n \frac{d^{3} y}{d x^{3}} = 0$

For each of the differential equations given below, indicate its order and degree (if defined).

(i)

(ii)

(iii)

\frac{d^{2} y}{d x^{2}} + 5 x {(\frac{d y}{d x})}^{2} - 6 y = log x

{(\frac{d y}{d x})}^{3} - 4 {(\frac{d y}{d x})}^{2} + 7 y = sin x

\frac{d^{4} y}{d x^{4}} - sin (\frac{d^{3} y}{d x^{3}}) = 0

{1, 2, 3, . . . . ., 8}

x^{3} \frac{d^{3} y}{d x^{3}} + x^{2} \frac{d^{2} y}{d x^{2}} + x \frac{d y}{d x} + y = 0

y^{2} = \frac{d y}{d x} (a + \sqrt[2]{{(\frac{d y}{d x})}^{3}}

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