Order of stability of carbocation is:

I > I I > I I I > I V

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I V > I I I > I > I I

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I V > I > I I > I I I

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I V > I I I > I I > I

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Solution

The correct option is B $I V > I I I > I > I I$
The carbocation(IV) is resonance stabilized and hence is the most stable. Among primary, secondary and tertiary carbocations, tertiary is the most stable while primary is the least stable due to decreasing $- I$ effect of the methyl group. Hence the order of stability of the carbocation is as follows

$I V (r e s o n a n c e s t a b i l i z e d) > I I I (t e r t i a r y) > I (s e c o n d a r y) > I I (p r i m a r y)$

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Similar questions

Arrange the following carbocations in decreasing order of stability

C l_{3} C^{+}

C l_{2} C H^{+}

C l C H_{2}^{+}

C H_{3}^{+}

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

K_{2} C O_{3} (I), M g C O_{3} (I I), C a C O_{3} (I I I), B e C O_{3} (I V)

The correct order for decreasing stability of the following free radicals is

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