Organic compounds A and B are the isomers with the molecular formula $C_{2} H_{6} O$ . Compound A produces hydrogen gas with sodium metal, whereas compound B does not. Compound A reacts with acetic acid in the presence of concentrated $H_{2} S O_{4}$ to form compound C with a fruity flavour. What are the isomers A, B and the compound C?

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Solution

1.Organic compound A-Ethyl alcohol / Ethanol)- $C_{2} H_{5} O H$
B-Dimethyl ether- $C H_{3} - O - C H_{3}$
2. Ethanol reacts with sodium metal to form sodium ethoxide and hydrogen gas $2 C_{2} H_{5} O H + 2 N a ⟶ 2 C_{2} H_{5} O N a + H_{2}$
3. Ethanol reacts with ethanoic acid in the presence of concentrated $H_{2} S O_{4}$
To form ethyl ethanoate and water fruity flower
$C_{2} H_{5} O H + C H_{3} C O O H c o n c . H_{2} S O_{4} - ------ \to C H_{3} C O O C_{2} H_{5} + H_{2} O$
A-Ethyl alcohol(Ethanol)- $C_{2} H_{5} O H$
B-Dimethyl ether - $C H_{3} O - C H_{3}$
C-Ethyl ethanoate- $C H_{3} C O O C_{2} H_{5}$

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C_{2} H_{6} O

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