Out of a total of 20 observations arranged is ascending order $10^{t h}$ and $11^{t h}$ observation are 40 and 44 What is the median ?

40

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42

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44

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45

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Solution

The correct option is B $42$
10th observation=40
11th observation=44
Median $= \frac{40 + 44}{2} = \frac{84}{2} = 42$

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