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Question

Out of butane, butan-1-ol, butanal, and butanone, the decreasing order of their boiling point is:

A
butane > butanol > butanal > butanone
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B
butanol > butane > butanal > butanone
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C
butanone > butanal > butanol > butane
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D
butanol > butanone>butanal > butane
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Solution

The correct option is D butanol > butanone>butanal > butane
The polar and stronger carbon-to-oxygen double bond result in increase dipole-dipole interaction which causes aldehydes and ketones to have higher boiling points than those of alkanes of similar molecular masses but lower than those of comparable alcohols that engage in intermolecular hydrogen bonding.

For ketones and aldehydes of similar molecular mass, ketones have higher boiling point due to the fact that its carbonyl group is more polarized than in aldehydes. So, interactions between molecules of ketones is stronger than between molecules of aldehydes, and that gives a higher boiling point so butanone has higher boiling point than butanal.
The decreasing order is
Butanol > butanone > butanal> butane
So, the correct option is (d)

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