Out of the following metals, which will give $H_{2}$ on reaction with $N a O H$ ?
$I : Z n$
$I I : M g$
$I I I : A l$
$I V : B e$

I, I I, I I I, I V

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I, I I I, I V

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I I, I V

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I, I I I

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Solution

The correct option is B $I, I I I, I V$
$Z n, A l$ and $B e$ will give hydrogen in reaction with $N a O H$ .
$M g$ is not affected by alkalies.
$Z n + 2 N a O H \to N a_{2} Z n O_{2} (s o d i u m z i n c a t e) + H_{2}$
$2 A l + 2 N a O H + 2 H_{2} O \to 2 N a A l O_{2} (s o d i u m m e t a a l u m i n a t e) + 3 H_{2}$
$2 A l + 6 N a O H f u s e - - \to 2 N a_{3} A l O_{3} (s o d i u m a l u m i n a t e) + 3 H_{2}$
$B e + 2 N a O H \to N a_{2} B e O_{2} + H_{2}$

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