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Redox Reactions

Out of the fo...

Question

Out of the following reduction process-

$A : {F e}_{2} O_{3} + C ⟶ F e + C O_{2}$
$B : Z n O + C ⟶ Z n + C O_{2}$
$C : S n O_{2} + C ⟶ S n + C O_{2}$
$D : P b O + C ⟶ P b + C O_{2}$

Correct processes are:

A l l

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A, B, D

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A, B, C

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B, D

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Solution

The correct option is A $A l l$
$A : {F e}_{2} O_{3} + C ⟶ F e + C O_{2}$
$B : Z n O + C ⟶ Z n + C O_{2}$
$C : S n O_{2} + C ⟶ S n + C O_{2}$
$D : P b O + C ⟶ P b + C O_{2}$

Carbon can be used to reduce the oxides of metals below aluminum in the Reactivity Series.
Since $F e, Z n, S n, P b$ are found below aluminum in reactivity series, therefore carbon can reduce all of them.
Hence, all of the given reduction processes given are correct.

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Similar questions

2 N a C l + C a C O_{3} \to N a_{2} C O_{3} + C a C l_{2}

C a C O_{3} Δ - \to [A] + [B]

N a C l + N H_{3} + [B] + H_{2} O \to [C] + [D]

2 [C] \to N a_{2} C O_{3} + H_{2} O + [B]

Of the following reduction processes :

I. $F e_{2} O_{3} + C \to F e$

II. $Z n O + C \to Z n$

III. $C a_{3} (P O_{4})_{2} + C \to P$

IV. $P b O + C \to P b$

A

N H_{4} C l

D

C O_{2}

B

C

+ N a O H \to N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O \to (B)

+ N a C l \to (C) + N H_{4} C l

\to N a_{2} C O_{3} + H_{2} O + (D)

C O_{2}

H_{2} O

O_{3}

O_{2}

C O_{2}

B e C l_{2}

S n C l_{2}

X e F_{2}

C_{2} H_{2}

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