Question

Out of the four arbitrary non-collinear points, three points are taken at a time, then the number of planes that can be drawn through the three points is:

• A. 3
• B. 4
• C. 6
• D. 12

Answer 1

The correct option is B 4

${}^4{C}_3=\frac{4!}{3!1!}=\frac{\mathrm{4.3.2.1}}{\mathrm{3.2.1.1}}=4$