wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Outer surface area of a hollow iron sphere is 1256 cm2. If the thickness of iron is 1 cm, find the volume of air inside the sphere. Take π=3.14


A

3052.08cm3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

3051.08cm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

3053.08cm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

3054.08cm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

3052.08cm3


Surface area of the sphere 4πr2 = 1256m2
4 × 3.14× r2=1256cm2
r=10cm
Thickness of the iron = 1cm
So, inner radius = 9 cm

Therefore, volume of air = inner volume of sphere
=43 ×π × r3
=43 × π × 93
=3052.08 cm3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Summary
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon