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Question

Outer surface area of a hollow iron sphere is 1256 cm2. If thickness of iron is 1 cm. Find its capacity.

A
3052 cm3
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B
1526 cm3
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C
6104 cm3
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D
9156 cm3
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Solution

The correct option is A 3052 cm3
Surface area of the sphere,
S=4πr2=1256 cm2
4×3.14×r2=1256 cm2
r=10 cm

Thickness of the iron = 1 cm
So, inner radius = 9 cm

Volume of air is euqal to the inner volume of sphere.
V=43πr3
V=43×3.14×93
V3052 cm3

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