Question

$\overleftrightarrow{AB}$ and $\overleftrightarrow{CD}$ intersect each other at point $O$. Measure of one angle is ${56}^{\circ }$, then find measure of other three angles.

Answer 1

Given that,

$\angle DOB={56}^0$

$\angle AOC=\angle DOB={56}^0\left[oppositeangle\right]$

$\angle AOD=180-56$

$={124}^0$

$\angle AOC=\angle COB={124}^0$

Required angles=${56}^0,{124}^0$