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Question

Limn[tanθ+12tanθ2++12ntanθ2n]=

A
1θ
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B
1θ2cotθ
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C
2cot2θ
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D
3
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Solution

The correct option is B 1θ2cotθ
cotαtanα=2cot2α
Ltn(2cot2θ+12ncotθ2n)=2cot2θ+Ltn12ntan(θ2n)=2cot2θ+1θ

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