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Question

CH3,NH2,OH,F in increasing pKb values

A
CH3,<NH2<OH<F
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B
F<OH<NH2<CH3
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C
OH<NH2<CH3<F
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D
none is correct
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Solution

The correct option is A CH3,<NH2<OH<F
In a period, basicity of anion increases as the pKb value and electronegative value decreases.

Electronegativity order is
F>O>N>C

So, F being the most electronegative atom, the pKb value will be the highest.

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