Oxalic acid is heated with concentrated $H_{2} S O_{4}$ . When the resultant gases are passed over red hot carbon, $X$ is obtained. Here, $X$ is:

C O

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C H_{4}

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C O_{2}

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C_{2} H_{4}

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Solution

The correct option is C $C O$
$(C O O H)_{2} + H_{2} S O_{4} (l) \to H_{2} O + C O_{2} (g) + C O (g) + H_{2} S O_{4} (l)$

When oxalic acid is heated with conc. sulfuric acid, a mixture of $C O$ and $C O_{2}$ is obtained.

$H_{2} C_{2} O_{4} H_{2} S O_{4} - --- \to - H_{2} O C O + C O_{2}$

When this mixture is passed over red hot carbon, $C O_{2}$ is reduced to $C O$ .

$C O + C O_{2} C - \to Δ 3 C O$

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