Oxidant and Reductanct in the following reactions are respectively
10H+(aq)+4Zn(s)+NO−3(aq)→4Zn2+(aq)+NH+4(aq)+3H2O(l)
First let us assign oxidation numbers in the equation.
10+1H+(aq)+40Zn(s)++5N−2O−3(aq)→4+2Zn2+(aq)+−3N+1H+4(aq)+3+1H2−2O(l)
Oxidation No. of Zn is increasing ⇒ Oxidising ⇒ Reductant
Oxidation No. of N is decreasing⇒ reducing ⇒ Oxidant
Oxidant : →N
Reductant: →Zn
Note ⇒ Oxidation is increase in oxidation in oxidation state while reduction is decrease in oxidation state.