Question

Oxidation number of bromine in sequence in $B{r}_3{O}_3$ is:

• A. +8, +6, +8
• B. +6, +4, +6
• C. 0, 0, 0
• D. +8, +4, +8

Answer 1

The correct option is B +6, +4, +6

$B{r}_3{O}_3$ is a tribromooctaoxide. The two Br at the terminal, have 3 oxygen atom attached, hence it's oxidation number is +6. The Br atom in the center have 2 oxygen atoms attached ,so it's oxidation state is +4. Hence, +6,4+6 is the sequence.