Oxidation number of carbon in $C H_{2} C l_{2}$ is :

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Solution

The correct option is D 0
Consider the oxidation state of carbon in dichloromethane as $x$ .
We know that the charges on $H$ and $C l$ are $+ 1$ and $- 1$ respectively.
Therefore, $C H_{2} C l_{2} \to x + 2 (+ 1) + 2 (- 1) = 0 \Rightarrow x = 0$
Hence option A is the correct answer of this question.

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